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Amazon Redshift
Database Developer Guide (API Version 2012-12-01)

Join Examples

The following query is an outer join. Left and right outer joins retain values from one of the joined tables when no match is found in the other table. The left and right tables are the first and second tables listed in the syntax. NULL values are used to fill the "gaps" in the result set.

This query matches LISTID column values in LISTING (the left table) and SALES (the right table). The results show that listings 2, 3, and 5 did not result in any sales.

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select listing.listid, sum(pricepaid) as price, sum(commission) as comm from listing left outer join sales on sales.listid = listing.listid where listing.listid between 1 and 5 group by 1 order by 1; listid | price | comm --------+--------+-------- 1 | 728.00 | 109.20 2 | | 3 | | 4 | 76.00 | 11.40 5 | 525.00 | 78.75 (5 rows)

The following query is an inner join of two subqueries in the FROM clause. The query finds the number of sold and unsold tickets for different categories of events (concerts and shows):

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select catgroup1, sold, unsold from (select catgroup, sum(qtysold) as sold from category c, event e, sales s where c.catid = e.catid and e.eventid = s.eventid group by catgroup) as a(catgroup1, sold) join (select catgroup, sum(numtickets)-sum(qtysold) as unsold from category c, event e, sales s, listing l where c.catid = e.catid and e.eventid = s.eventid and s.listid = l.listid group by catgroup) as b(catgroup2, unsold) on a.catgroup1 = b.catgroup2 order by 1; catgroup1 | sold | unsold -----------+--------+-------- Concerts | 195444 |1067199 Shows | 149905 | 817736 (2 rows)

These FROM clause subqueries are table subqueries; they can return multiple columns and rows.