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s3_deletebucketwebsite.js

s3_deletebucketwebsite.js demonstrates how to delete the website configuration from an Amazon S3 bucket.

/** * Copyright 2010-2019 Amazon.com, Inc. or its affiliates. All Rights Reserved. * * This file is licensed under the Apache License, Version 2.0 (the "License"). * You may not use this file except in compliance with the License. A copy of * the License is located at * * http://aws.amazon.com/apache2.0/ * * This file is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR * CONDITIONS OF ANY KIND, either express or implied. See the License for the * specific language governing permissions and limitations under the License. */ // ABOUT THIS NODE.JS SAMPLE: This sample is part of the SDK for JavaScript Developer Guide topic at // https://docs.aws.amazon.com/sdk-for-javascript/v2/developer-guide/s3-example-static-web-host.html // Load the AWS SDK for Node.js var AWS = require('aws-sdk'); // Set the region AWS.config.update({region: 'REGION'}); // Create S3 service object s3 = new AWS.S3({apiVersion: '2006-03-01'}); var bucketParams = {Bucket: process.argv[2]}; // call S3 to delete website configuration for selected bucket s3.deleteBucketWebsite(bucketParams, function(error, data) { if (error) { console.log("Error", err); } else if (data) { console.log("Success", data); } });

Sample Details

Service: s3

Last tested: 2018-06-02

Author: AWS-JSDG

Type: full-example

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