建立陣列 - Amazon Athena

本文為英文版的機器翻譯版本,如內容有任何歧義或不一致之處,概以英文版為準。

建立陣列

若要在 Athena 中建置陣列常值,請使用 ARRAY 關鍵字,後面接著方括弧 [ ] 並包含陣列元素 (以逗號分隔)。

範例

此查詢會建立具有四個元素的陣列。

SELECT ARRAY [1,2,3,4] AS items

它會傳回:

+-----------+ | items | +-----------+ | [1,2,3,4] | +-----------+

此查詢會建立兩個陣列。

SELECT ARRAY[ ARRAY[1,2], ARRAY[3,4] ] AS items

它會傳回:

+--------------------+ | items | +--------------------+ | [[1, 2], [3, 4]] | +--------------------+

若要從選取的相容類型資料欄建立陣列,請使用查詢,如此範例所示:

WITH dataset AS ( SELECT 1 AS x, 2 AS y, 3 AS z ) SELECT ARRAY [x,y,z] AS items FROM dataset

此查詢會傳回:

+-----------+ | items | +-----------+ | [1,2,3] | +-----------+

在以下範例中,選取了兩個陣列,並以歡迎訊息傳回。

WITH dataset AS ( SELECT ARRAY ['hello', 'amazon', 'athena'] AS words, ARRAY ['hi', 'alexa'] AS alexa ) SELECT ARRAY[words, alexa] AS welcome_msg FROM dataset

此查詢會傳回:

+----------------------------------------+ | welcome_msg | +----------------------------------------+ | [[hello, amazon, athena], [hi, alexa]] | +----------------------------------------+

若要建立一系列的金鑰值組,請使用 MAP 運算子,其會使用一系列的金鑰,接著是一系列的值,如此範例所示:

SELECT ARRAY[ MAP(ARRAY['first', 'last', 'age'],ARRAY['Bob', 'Smith', '40']), MAP(ARRAY['first', 'last', 'age'],ARRAY['Jane', 'Doe', '30']), MAP(ARRAY['first', 'last', 'age'],ARRAY['Billy', 'Smith', '8']) ] AS people

此查詢會傳回:

+-----------------------------------------------------------------------------------------------------+ | people | +-----------------------------------------------------------------------------------------------------+ | [{last=Smith, first=Bob, age=40}, {last=Doe, first=Jane, age=30}, {last=Smith, first=Billy, age=8}] | +-----------------------------------------------------------------------------------------------------+